Create a dictionary with roll number, name and marks of n students in a class and display the names of students who have scored marks above 75 in python

• Here ,We are going to create a dictionary with roll number, name and marks of n students in a class and display the names of students who have scored marks above 75 in python. We can use for loop to enter number of students in dictionary. With the help of if else loop,we can check the number of students who got more than 75 percentage marks .

Python program to create dictionary

# Python Program to find Student Grade
n = int(input("Enter number of students :"))
result = {}
for i in range(n):
    print("Enter Details of students :",i+1)
    rno = int(input("Roll number :"))
    name = input("Name :")
    english = float(input("Enter English Marks: "))
    math = float(input("Enter Math score: "))
    computers = float(input("Enter Computer Marks: "))
    physics = float(input("Enter Physics Marks: "))
    chemistry = float(input("Enter Chemistry Marks: "))
    total = english + math + computers + physics + chemistry
    percentage = (total / 500) * 100
    result[rno] = [name,percentage]
print(result)

for s in result:
    if result[s][1]>75:
      print("Following students having more than 75 marks:")
      print(result[s][0])

Output:

Enter number of students :3
Enter Details of students : 1
Roll number :3
Name :Sumedh
Enter English Marks: 77
Enter Math score: 88
Enter Computer Marks: 99
Enter Physics Marks: 67
Enter Chemistry Marks: 56
Enter Details of students : 2
Roll number :2
Name :Sushil
Enter English Marks: 78
Enter Math score: 55
Enter Computer Marks: 66
Enter Physics Marks: 44
Enter Chemistry Marks: 77
Enter Details of students : 3
Roll number :8
Name :Anita
Enter English Marks: 66
Enter Math score: 22
Enter Computer Marks: 11
Enter Physics Marks: 44
Enter Chemistry Marks: 33
{3: ['Sumedh', 77.4], 2: ['Sushil', 64.0], 8: ['Anita', 35.199999999999996]}
Following students having more than 75 marks:
Sumedh

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